Convert list to variable arguments?

[Tim Johnson]

Let's suppose I have a function foo

Code Select Expand

(define (foo)
    (doargs (i) (println i)))
and I can process it by something like this:

Code Select Expand

(foo a b c x e f g)

Now, suppose I have a list that looks like this:

Code Select Expand


(set 'lst '(a b c x e f g))
Is there a method to pass 'lst to 'foo so that it is consumend

one item at a time by 'doargs?

Thanks

tim

[Jeff]

(cons foo lst)

[Lutz]

like this:

Code Select Expand

> (apply foo lst)
a
b
c
x
e
f
g
g
>


[Tim Johnson]

(cons foo lst)

Code Select Expand


> (cons foo lst)
((lambda ()
  (doargs (i)
   (println i))) a b c x e f g)
;; That doesn't evaluate 'foo with 'lst...

;; Or did I miss something?

Thanks

tim

[Lutz]

we posted together ;-) the answer again:

Code Select Expand

> (apply foo lst)
a
b
c
x
e
f
g
g
>


[Tim Johnson]

we posted together ;-) the answer again:

Code Select Expand

> (apply foo lst)
a
b
c
x
e
f
g
g
>


Yes! Thank you sir!

[Lutz]

Jeff just forgot to wrap an 'eval' around his answer, but there is a difference between both approaches:

Code Select Expand

(eval (cons foo lst))


This would give all nil's because a,b,c,d,e,f,g would be evaluated to their contents. It depends what you want, the contents of the symbols a to g or the symbols a to g themselves when using 'apply'.