list to values

[jopython]

Lets say I have a function which accepts 2 strings and three integers

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e.g
(myfunc "str1" "str2" 3 4 5)

However I have a list which contains these integer values.

(setq myvalues '(3 4 5))

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How can I convert the content of myvalues list to a set of values so that i can pass them to "myfunc" as arguments?


[HPW]

Like this:

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(setq myvalues '(3 4 5))
(myfunc "str1" "str2" (myvalues 0)(myvalues 1)(myvalues 2))


?

[jopython]

HPW,



This is not possible if myvalues has a 'unknown' number of elements.

[Lutz]

try  using the following three functions:



http://www.newlisp.org/downloads/newlisp_manual.html#apply">http://www.newlisp.org/downloads/newlis ... html#apply">http://www.newlisp.org/downloads/newlisp_manual.html#apply

http://www.newlisp.org/downloads/newlisp_manual.html#append">http://www.newlisp.org/downloads/newlis ... tml#append">http://www.newlisp.org/downloads/newlisp_manual.html#append

http://www.newlisp.org/downloads/newlisp_manual.html#list">http://www.newlisp.org/downloads/newlis ... .html#list">http://www.newlisp.org/downloads/newlisp_manual.html#list

[William James]

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(define (my-func s1 s2 a b c)
  (dup (string s1 s2 a b) c))

> (my-func "o" "-" 1984 9 3)
"o-19849o-19849o-19849"

> (apply my-func (cons "o" (cons "-" '(1984 9 3))))
"o-19849o-19849o-19849"

> (apply my-func (append '("o" "-") '(1984 9 3)))
"o-19849o-19849o-19849"