Command line: passing open arg ?

[DavMin]

I'm running a single program in newlisp and want to pass an argument:



newlisp dl.lsp '123456'



I doesn't seem like newlisp accepts openargs. Did I miss something?



I suppose I could write it to a text file and have the program read the text file to retrieve the info :(

[DavMin]

I see I need to link it into an exe, then I can pass cmd line args. Thanks.

[Lutz]

You don't need to link to an .exe to get the command line parameters. If your dl.lsp is:

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(println "The command line args are: " (main-args))
(println "The last one is: " (int (main-args -1)))
(exit)

then:

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~> newlisp dl.lsp 12345
The command line args are: ("newlisp" "dl.lsp" "12345")
The last one is: 12345
~>

Note, that all arguments are passed as strings, even if not quoted.



On UNIX you could add as first line in the script:

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#!/usr/bin/newlisp

(println "The command line args are: " (main-args))
(println "The last one is: " (int (main-args -1)))
(exit)

After giving dl.lsp executable permissions, you can do:

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~> ./dl.lsp 12345
The command line args are: ("/usr/bin/newlisp" "./dl.lsp" "12345")
The last one is: 12345
~>


[DavMin]

Very cool. Thank you!