Print Page - map trim command on list members

Title: map trim command on list members
Post by: vetelko on October 19, 2016, 02:46:56 AM

Hi guys,

how can I map trim command to list members?

say I have list like this:

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(set 'lst '("a." "b " "c"))

and I want to trim dot character trying this construct:

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(set 'lst2 (map (curry trim {.}) lst))

but it doesn't work, output is:

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("." "." ".")

Title: Re: map trim command on list members
Post by: rrq on October 19, 2016, 03:43:22 AM

If you try it out by hand, as in

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> (curry trim ".")
(lambda ($x) (trim "." $x))

you see that the curried function is not exactly what you want.

You rather need to use a function like

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(fn ($x) (trim $x "."))

instead; there's no abbreviation macro for that order of arguments.

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