Print Page - string function returns literal list

Title: string function returns literal list
Post by: sigipa on October 18, 2016, 06:43:50 PM

Hello All,

When the string function is applied to a list, it returns a literal list. See code below.

(string '("a" "b" "c"))

This returns: ("a" "b" "c")

I expected it to return: "abc"

Is this working as intended? If so, is there another function that will return a string without the parens and quotes?

Thanks,

-S

Title: Re: string function returns literal list
Post by: steloflute on October 18, 2016, 09:13:12 PM

It is intended. See //http://www.newlisp.org/downloads/newlisp_manual.html#string

~~Quote~~Translates into a string anything that results from evaluating exp-1—. If more than one expression is specified, the resulting strings are concatenated.

Code Select Expand (string 'hello) → "hello" (string 1234) → "1234" (string '(+ 3 4)) → "(+ 3 4)" (string (+ 3 4) 8) → "78" (string 'hello " " 123) → "hello 123"

I suggest using apply as follows:

Code Select Expand
> (apply string '("a" "b" "c"))
"abc"

Title: Re: string function returns literal list
Post by: sigipa on October 19, 2016, 05:24:54 AM

Hi,

Works perfectly. Thanks.

-S

Title: Re: string function returns literal list
Post by: kesha on November 10, 2016, 05:04:36 PM

Hi,

//http://www.newlisp.org/downloads/newlisp_manual.html#join

Code Select Expand

> (set 'MYLIST '("a" "b" "c"))
("a" "b" "c")
> (join MYLIST)
"abc"
> (join MYLIST "-")
"a-b-c"
> (join MYLIST (string "-" (join MYLIST) "-"))
"a-abc-b-abc-c"

newLISP Fan Club

Forum => newLISP in the real world => Topic started by: sigipa on October 18, 2016, 06:43:50 PM