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Forum => Anything else we might add? => Topic started by: ssqq on January 02, 2015, 03:59:04 AM

Title: function *replace* could not catch $0, $1 in Ubuntu 14.04
Post by: ssqq on January 02, 2015, 03:59:04 AM
When I test *repace* in ubuntu 14.04, I found following test would fail:



      (set 'str "---axb--ayb---")

      (replace "(a)(.)(b)" str (append $3 $3 $1) 0)

      (= str "---bxa---bya---")
Title: Re: function *replace* could not catch $0, $1 in Ubuntu 14.0
Post by: Lutz on January 02, 2015, 06:40:53 AM
Look at your code again. You probably mean:


Code Select

>
(set 'str "---axb--ayb---")
(replace "(a)(.)(b)" str (append $3 $2 $1) 0)
(= str "---bxa--bya---")

"---axb--ayb---"
"---bxa--bya---"
true
>
Title: Re: function *replace* could not catch $0, $1 in Ubuntu 14.0
Post by: ssqq on January 04, 2015, 10:35:03 PM
yes, I write error code.



I found the int-option in replace is could not ignore like *regex*. if ignore the int-option, newLISP would make "find-str" as *literal str*, if add int-option, newLISP would treat *find-str* as *regex-str".



    (replace "(a)" "aabb" "c")

    => "aabb"

    > (replace "(a)" "aabb" "c" 0)

    => "ccbb"
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