Print Page - list to values

Title: list to values
Post by: jopython on December 07, 2012, 06:20:31 PM

Lets say I have a function which accepts 2 strings and three integers

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e.g
(myfunc "str1" "str2" 3 4 5)

However I have a list which contains these integer values.

(setq myvalues '(3 4 5))

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How can I convert the content of myvalues list to a set of values so that i can pass them to "myfunc" as arguments?

Title: Re: list to values
Post by: HPW on December 07, 2012, 11:09:17 PM

Like this:

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(setq myvalues '(3 4 5))
(myfunc "str1" "str2" (myvalues 0)(myvalues 1)(myvalues 2))

Title: Re: list to values
Post by: jopython on December 08, 2012, 04:33:21 AM

HPW,

This is not possible if myvalues has a 'unknown' number of elements.

Title: Re: list to values
Post by: Lutz on December 08, 2012, 07:03:00 AM

try using the following three functions:

http://www.newlisp.org/downloads/newlisp_manual.html#apply

http://www.newlisp.org/downloads/newlisp_manual.html#append

http://www.newlisp.org/downloads/newlisp_manual.html#list

Title: Re: list to values
Post by: William James on December 21, 2012, 07:11:55 AM

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(define (my-func s1 s2 a b c)
  (dup (string s1 s2 a b) c))

> (my-func "o" "-" 1984 9 3)
"o-19849o-19849o-19849"

> (apply my-func (cons "o" (cons "-" '(1984 9 3))))
"o-19849o-19849o-19849"

> (apply my-func (append '("o" "-") '(1984 9 3)))
"o-19849o-19849o-19849"

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Forum => newLISP in the real world => Topic started by: jopython on December 07, 2012, 06:20:31 PM