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Forum => newLISP in the real world => Topic started by: didi on January 09, 2012, 11:06:04 AM

Title: List indexing
Post by: didi on January 09, 2012, 11:06:04 AM
; implicit indexing from "Code Patterns"



(set 'L '(a b (c d (e f) g) h i))



(L 2 2 1) → f

(L 2 2)   → (e f)



Is there a reverse function to get the vector of an  element in a nested list ?

Is it right, that the  find function principally does this,  but only in the highest level ?



For example

(find 'a L ) -> 0

(find 'b L ) -> 1

(find 'c L ) -> nil ?
Title: Re: List indexing
Post by: johu on January 09, 2012, 02:41:47 PM
from newLISP Manual and Reference (//http)


QuoteTo find expressions in nested or multidimensional lists, use the ref and ref-all functions.


Then,
Code Select
> (set 'L '(a b (c d (e f) g) h i))
(a b (c d (e f) g) h i)
> (ref 'b L)
(1)
> (ref 'c L)
(2 0)
> (ref 'f L)
(2 2 1)
>
Title: Re: List indexing
Post by: didi on January 09, 2012, 10:08:49 PM
Super,  thankyou !
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