Trivial:
> (for (i 1 10 1) (println i))
1
2
3
4
5
6
7
8
9
10
Now this:
> (import "msvcrt.dll" "printf")
printf<7714C5B9>
> (for (i 1 10 1) (printf "%in" i))
0
0
0
0
0
0
0
0
0
0
Could someone please explain what is going on here ?
My guess: You import the DLL-function printf and call it. The 0 is the returned value from the function-call.
The variable type of i is maybe `double' (newlisp's float type).
printf %i (dll or libc.so) requires a `int' argument.
Therefore, the output will be broken because of type mismatches.
The solution is use "int" function, or %f, %g format.
(printf "%gn" i)
# P.S.
If num-step (`for' primive argument) is not specified, the variable type i will be `int' .