I`m trying to make function curry-all, and my macro works, but... looks too ugly to be correct.
(letex (f1 f lst (map string (args)))
(fn (z) (eval-string (append "(" (name 'f1) " " (join 'lst " ") " " (name 'z) ")")))))
((curry-all + 1 2 3 4) 5)
> 15
I think, there should be some easier way to ask LISP to expand args, right?
You don't need string operations and 'eval-string'. Compose and manipulate your lambda expressions directly using list functions:
(append (lambda (z)) (list (cons f (append (args) '(z))))))
((curry-all + 1 2 3 4) 5) => 15
here is another solution using expand, but its slower:
(letex (body (cons f (append (args) '(z))))
(lambda (z) body)))
Thanx, lambdas cleared for me a bit. I was surprised by timing: 0,031 ms for eval-string method and 0,0015 ms for the cons ones.
Btw, why is there 40E3BF in the expression?
(append (lambda (z)) (list (cons f (append (args) '(z))))))
(curry-all + 1)
=> (lambda (z) (+ <40E3BF> 1 z))
Quote
that is the way an evaluated built-in function symbol gets displayed (the internal machine hex-adddress). If you would quote it, you wouldn't see it:
(append (lambda (z)) (list (cons f (append (args) '(z))))))
(curry-all '+ 1)
=> (lambda (z) (+ 1 z))
passing it unquoted will be a tiny bit faster.
ps:
will return the same value.