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Title: dup
Post by: Jeremy Dunn on February 06, 2009, 11:51:07 AM

Lutz,

Why not make DUP take additional multiplier arguments so that

(dup x n1 n2 n3 ....) is the same as (dup (dup (dup x n1) n2) n2)? That way if I want a 3x3 matrix of zeros I can write (dup 0 3 3) instead of (dup (dup 0 3) 3).

Title:
Post by: newBert on February 07, 2009, 11:55:07 AM

Maybe you can do also:

Code Select Expand
(dup (series 0 0 3) 3)
;-> ((0 0 0) (0 0 0) (0 0 0))

~~Quote from: "Manual and Reference"~~ (series num-start num-factor num-count)

In the first syntax, series creates a geometric sequence with num-count elements starting with the element in num-start. Each subsequent element is multiplied by num-factor.

~~P.S.: sorry, i just realize that it amounts to the same thing :-/~~

Title:
Post by: newBert on February 10, 2009, 01:26:45 AM

Try this way instead:
Code Select Expand > (array 3 3 '(0)) ((0 0 0) (0 0 0) (0 0 0))
;o)

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Forum => newLISP newS => Topic started by: Jeremy Dunn on February 06, 2009, 11:51:07 AM