Function to create a function with name and parameters:
(let (f nil)
(setq f (string "(define (" name " x) (+ " val " x))"))
(setq name (eval-string f))
name))
Creating a function
out: (lambda (x) (+ 10 x))
Using the created function
out: 13
Do you know of another way (instead of using strings) to create a function with another function?
Maybe this way, but it's not quite the same:
(define (make-adder x)
(letex (x y)
(fn (z) (+ y z))))
(setq add2 (make-adder 2))
(println (add2 4))
> 6
Thank you, but it doesn't works. The symbol y is not binded.
I am looking for the most suitable/fastest method of generating functions automatically (passing name of function and parameters).
Oh my apologies! I reversed x and y (in `letex`) when transcribing... :/
(letex (y x)
(fn (z) (+ y z))))
(setq add2 (make-adder 2))
(println (add2 4))
; 6
It works.
But I would also need to pass the function name as a parameter, for example:
Thanks again for the help
So, maybe like this (probably improvable):
(define-macro (make-adder) (local (name val) (bind (args) true) (set (expand name 'name) (expand (lambda (x) (+ val x)) 'val))))
(make-adder (name 'add10) (val 10))
(println (add10 3))
; 13
Sorry, I could not indent the previous code, because it caused an "internal server error" (?!)
Thanks again.
I'll test both methods for speed and simplicity.
Quote from: cameyo post_id=25005 time=1617113250 user_id=732
Function to create a function with name and parameters:
(let (f nil)
(setq f (string "(define (" name " x) (+ " val " x))"))
(setq name (eval-string f))
name))
Creating a function
out: (lambda (x) (+ 10 x))
Using the created function
out: 13
Do you know of another way (instead of using strings) to create a function with another function?
your example of a made-add function to create a sum-10 function:
(define (make-add n v)
(evaluate (list 'define (list n 'x) (list '+ v 'x))))
and using it:
(make-add 'sum-10 10)
out: (lambda (x) (+ 10 x))
(sum-10 3)
out: 13
a more general way to create any funcion with name n having parameters a and a body b with minor checking of parameters and function name:
(define (mkf n a b)
(evaluate (and (symbol? n) (list 'define (if (apply and (map symbol? (cons n a))) (cons n a) n) b))))
and using it:
(mkf 'sum-x-y '(x y) '(+ x y))
out: (lambda (x y) (+ x y))
sum-x-y
out: (lambda (x y) (+ x y))
(sum-x-y 4 5)
out: 9
the function expects name and parameters to be symbols and defaults to a symbol definition if you pass bad parameters, that is paremeters which are not symbols, in this case is defines a symbol with the name passed and the evaluated body as value (or nil if evaluation fails). If the name of the function to be defined is not a symbols it returns nil and doesn't define anything:
x
out: nil
y
out: nil
(mkf 'sum-x-y-with-bad-parameters '(x y 3) '(+ x y))
out: ERR
sum-x-y-with-bad-parameters
out: nil
(define x 3)
out: 3
(define y 34)
out: 34
(mkf 'sum-x-y-with-bad-parameters '(x y 3) '(+ x y))
out: 37
sum-x-y-with-bad-parameters
out: 37
(mkf 4 '(x y 3) '(+ x y))
out: nil
(mkf nil '(x y) '(+ x y))
out: nil
Take this as an example about how to face the question, of course it needs more checking to be robust and correct (variable capture...).
Note: in this post "evaluate" means "eval", because phpBB does not allow me to type it even in code section, so assume this code as the very begining:
Thanks pda